W = Σ F Δx
Elastic energy is the work you put into stretching the string. The
lever rotates, the string gets longer, and the force climbs. You
already have force at known angles out to 180°. That is enough. Add
the work from each slice. Do not multiply peak force by the whole
swing, and do not treat the Vernier F vs t area as joules.
What you measured
The mousetrap arm is a lever. As it rotates, it pulls the string
farther out, so the force on the Vernier hook goes up. You held the
hook at a set of angles and read F at each one, ending at 180°,
maximum extension.
Work still needs a distance. The angles are how you get that
distance. Measure r once, pivot to where the string or
Vernier hook actually sits.
How to add the slices
For each neighboring pair of points, from the start angle out to 180°:
Δθ = (θ₂ − θ₁) × π/180
Δx = r Δθ
W_step = ((F₁ + F₂) / 2) × Δx
Δθ has to be radians. Degrees in the table stay degrees until that
first line. The average of the two forces is the trapezoid. Add every
W_step. That sum is the energy stored at max extension.
If you marked string length
If you also wrote down string length, or how far the hook actually
moved, at each angle, use those x values instead of
r Δθ. Same formula. Better if the string does not follow
a clean arc.
W_step = ((F₁ + F₂) / 2) × (x₂ − x₁)
One slice, so the units are obvious
W for that slice
5.5 × 0.0524 = 0.288 J
Repeat that to 180° and add. The 0.288 J is only 30° to 60°. The lab
number is the whole sum.
What the Vernier graph is not
Vernier's default plot is F vs t. The area under that curve is
impulse, N·s, not joules. Ignore time if you already have F at known
angles.
If you pulled at a roughly constant slow speed instead of discrete
holds, the same idea still needs a distance.
W = v × (area under F vs t) only works because
Δx = v Δt. You still measured a speed. You still did not
call the raw integral the energy.
Do not do F_max × the full swing. Force changes with
angle. That is why you took the steps.